{"id":5636,"date":"2013-12-29T20:45:49","date_gmt":"2013-12-30T01:45:49","guid":{"rendered":"http:\/\/spinor.info\/weblog\/?p=5636"},"modified":"2014-01-08T14:56:14","modified_gmt":"2014-01-08T19:56:14","slug":"pointless-mathematics","status":"publish","type":"post","link":"https:\/\/spinor.info\/weblog\/?p=5636","title":{"rendered":"Pointless mathematics"},"content":{"rendered":"<p>The other day, I ran across a <a href=\"https:\/\/plus.google.com\/117663015413546257905\/posts\/Cn64ju8z11a\">cute geometry puzzle<\/a> on John Baez&#8217;s Google+ page. I was able to solve it in a few minutes, before I read the full post that suggested that this was, after all, a harder-than-usual area puzzle. Glad to see that, even though the last high school mathematics competition in which I participated was something like 35 years ago, I have not yet lost the skill.<\/p>\n<p>Anyhow, the puzzle is this: prove that the area of the two semicircles below is exactly half the area of the full circle.<\/p>\n<p style=\"text-align: center;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter  wp-image-5637\" alt=\"\" src=\"\/weblog\/wp-content\/uploads\/2013\/12\/puzzle-unlabeled.gif\" width=\"346\" height=\"346\" \/><\/p>\n<p>I am going to insert a few blank lines here before providing my solution.<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>I start with labeling some vertices on the diagram and also drawing a few radii and other lines to help.<\/p>\n<p style=\"text-align: center;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter  wp-image-5638\" alt=\"\" src=\"\/weblog\/wp-content\/uploads\/2013\/12\/puzzle.gif\" width=\"356\" height=\"356\" \/><\/p>\n<p>Next, let&#8217;s call the radii of the two semicircles as \\(a\\) and \\(b\\). Then, we have<br \/>\n\\begin{align}<br \/>\n(AC)&amp;= a,\\\\<br \/>\n(BD)&amp;= b.<br \/>\n\\end{align}Now observe that<br \/>\n\\begin{align}<br \/>\n(OA) = (OB) = r,<br \/>\n\\end{align}and also<br \/>\n\\begin{align}<br \/>\n(CD)&amp;= a + b,\\\\<br \/>\n(OD)&amp;= a + b~- (OC).<br \/>\n\\end{align}The rest is just repeated application of the theorem of Pythagoras:<br \/>\n\\begin{align}<br \/>\n(OC)^2&amp;= r^2 &#8211; a^2,\\\\<br \/>\n(OD)^2&amp;= r^2 &#8211; b^2,<br \/>\n\\end{align}followed by a bit of trivial algebra:<br \/>\n\\begin{align}<br \/>\n(OC)^2 + a^2&amp;= [a + b &#8211; (OC)]^2 + b^2,\\\\<br \/>\n0&amp;= 2(a + b)[b &#8211; (OC)],\\\\<br \/>\n(OC)&amp;= b.<br \/>\n\\end{align}Therefore,<br \/>\n\\begin{align}<br \/>\na^2+b^2=r^2,<br \/>\n\\end{align}which means that the area of the full circle is twice the sum of the areas of the two semicircles, which is what we set out to prove.<\/p>\n<p>I guess I have not yet lost my passion for pointless, self-serving mathematics.<\/p>\n<fb:like href='https:\/\/spinor.info\/weblog\/?p=5636' send='true' layout='standard' show_faces='true' width='450' height='65' action='like' colorscheme='light' font='lucida grande'><\/fb:like>","protected":false},"excerpt":{"rendered":"<p>The other day, I ran across a cute geometry puzzle on John Baez&#8217;s Google+ page. I was able to solve it in a few minutes, before I read the full post that suggested that this was, after all, a harder-than-usual area puzzle. Glad to see that, even though the last high school mathematics competition in <a href='https:\/\/spinor.info\/weblog\/?p=5636' class='excerpt-more'>[&#8230;]<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[30],"tags":[],"class_list":["post-5636","post","type-post","status-publish","format-standard","hentry","category-mathematics","category-30-id","post-seq-1","post-parity-odd","meta-position-corners","fix"],"_links":{"self":[{"href":"https:\/\/spinor.info\/weblog\/index.php?rest_route=\/wp\/v2\/posts\/5636","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/spinor.info\/weblog\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/spinor.info\/weblog\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/spinor.info\/weblog\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/spinor.info\/weblog\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=5636"}],"version-history":[{"count":9,"href":"https:\/\/spinor.info\/weblog\/index.php?rest_route=\/wp\/v2\/posts\/5636\/revisions"}],"predecessor-version":[{"id":5696,"href":"https:\/\/spinor.info\/weblog\/index.php?rest_route=\/wp\/v2\/posts\/5636\/revisions\/5696"}],"wp:attachment":[{"href":"https:\/\/spinor.info\/weblog\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=5636"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/spinor.info\/weblog\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=5636"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/spinor.info\/weblog\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=5636"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}